SpletThe line l1 has equation y = −2x + 3. The line l2 is perpendicular to l1 and passes through the point (5, 6). (a) Find an equation for l2 in the form ax + by + c = 0, where a, b and c are integers. The first thing to look at is l2 and l1 being perpendicular. This means the gradients of the two lines multiplied together = -1 . SpletThe line l1 has equation 2x + 4y – 3 = 0. The line l2 has equation y = mx + 7, where m is a constant. Given that l1 and l2 are perpendicular, (a) find the value of m. The lines l1 and …
Solve -3x+4y=8 Microsoft Math Solver
Splet07. jan. 2024 · Solution: A line through (-5, 2) and (1, -4) is perpendicular to the line through (x, -7) and (8, 7). Solution: The line 2x–3y+2=0 is perpendicular to another line L1 of … SpletClick here👆to get an answer to your question ️ A line 4x + y = 1 through the point A (2, - 7) meets the line BC whose equation is 3x - 4y + 1 = 0 at the point B . Find the equation to the line AC . such that AB = AC . see friends on spotify app
Coordinate Geometry: Straight Lines - PMT
SpletLet L 1 =3x+4y=1 and L 2 = 5x-12y=0 be two given lines , Let image of every point on L 1, with respect to a line L lies on L 2 then possible equation of L can be A 14x+112y-23=0 B … Splet14. feb. 2024 · The line through ( 2, 4, 5) perpendicular to the plane 3 x + 7 y − 5 z = 21 I know that to get the parametric equations of a line, you need a vector parallel to that line and a point on the line. So question 1) seems pretty straightforward. The vector P Q → =< 2, − 1, 3 > is obviously parallel to the line since it includes the line. Splet3. Find the equation of the plane that contains the point (1;3;0) and the line given by x = 3 + 2t, y = 4t, z = 7 t. Lots of options to start. We know a point on the line is (1;3;0). The line has direction h2; 4; 1i, so this lies parallel to the plane. Now we need another direction vector parallel to the plane. Plugging 3 see full folder path in file explorer