Show that 12n cannot end with the digit 0
WebToppr WebMar 29, 2024 · Ex 1.2 , 5 Check whether 6n can end with the digit 0 for any natural number n. Let us take the example of a number which ends with the digit 0 So, 10 = 2 5 100 = 2 2 5 5 …
Show that 12n cannot end with the digit 0
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WebNov 27, 2024 · Solution: If the number 12n, for any natural number n, ends with the digit 0 or 5, then it is divisible by 5. That is, the prime factorization of 12n contains the prime 5. This … WebShow that 12^n cannot end with the digit 0 or 5 for any natural number n. http://wp.me/p5C9z4-jd
WebThe prime factors of 12 are 2 and 3. 12 = 2 2 × 3 ⇒ 12 n = 2 2 n × 3 n. Since, 5 is not the factor of 12 n. Therefore, for any value of n, 12 n will not be divisible by 5. Hence, 12 n … WebApr 6, 2024 · Best answer As we know that 15n = (3 x 5)n = 3n x 5n The prime factorization of 15 doesn't have a 2 and 5 as its factor. So, its factorization will never end in 10 as a number ending in 10 must have a factors as 5 and 2. So, 15n will never end in zero as 15 doesn't has 2 as a factor. ← Prev Question Next Question → Find MCQs & Mock Test
WebIf 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. ⇒ 12n = (22 × … WebJun 7, 2015 · 12n can only end with digits 0 or 5 when it base prime factors include 2 and 5 as its factors. but 12 has not 2 and 5 as its prime factors . so it is impossible for 12n to …
WebApr 9, 2024 · EXAMPLE 5 Show that 1 2 n cannot en SOLUTION Expressing 12 as the product of primes, we obtain 12 ⇒ 1 2 n = 2 2 × 3 = (2 2 × 3) n = (2 2) n × 3 n = (2) 2 n × 3 n So, only primes in the factorisation of 1 2 n are 2 and 3 and, not 5 . Hence, 1 2 n cannot end with digit 0 or 5. LEVEL-2 EXAMPLE 6 Show that thereare infinitely many positive ...
WebSolution. If any number ends with the digit 0 or 5. It is always divisible by 5. If 12 n ends with the digit zero or five it must be divisible by 5. This is possible only if prime factorisation of … nicole fisher investments cpimseWeb8 rows · Mar 17, 2024 · SHORT ANSWER TYPE QUESTIONS-I 18. Show that 1 2 n cannot end with the digit 0 or 5 for any natural ... no wine\\u0027s landWebIf any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. 12 = 2 × 2 × 3 = 22 × 3 ⇒ 12n = (22 × 3)n = 22n × 3n Since its prime factorisation does not contain 5. nicole fish fischer travelWebMar 19, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number n. Viewed by: 5,029 students Updated on: Mar 19, 2024 1 student asked the same question on Filo Learn from their 1-to-1 discussion with Filo tutors. 3 mins Uploaded on: 3/19/2024 Taught by Adarsh Tiwari Connect instantly with this tutor Connect now nicole fields photographyWebJun 16, 2024 · If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. Step-by-step explanation: nicole fitts springfield moWebJul 31, 2024 · Answer: 12^n cannot end with digit 0 or 5 Step-by-step explanation:12^n has multiples= 2×2×3. Since the multiples of 12 do not contain 5 therefore it cannot end with 0 or5 This is because if any no. Is ending with 5 then it must have atleast one 5 in its multiples and if any no. Ends with 0 then it must have a pair of 5&2 as its multiples nicole fitch artistWebApr 2, 2012 · Here, Number=12 n where n stand for any natural number . Now , For 12 n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with … no wine untasted