WebA string is said to be palindrome if it the same string when reversed. Example 1: Input: s = "abcbdd" Output: true Explanation: "abcbdd" = "a" + "bcb" + "dd", and all three substrings are palindromes. Example 2: Input: s = "bcbddxy" Output: false Explanation: s cannot be split into 3 palindromes. Constraints: 3 <= s.length <= 2000 WebApr 3, 2024 · To check whether it’s a palindrome or not, iterate on string by taking two pointers. Initialize the first to start and other to end of string. If both characters are same …

Palindrome Partitioning - TutorialCup

WebThe palindrome substrings are {“a”, ”c”, “abba”, “d”, “ee”, “ff”}. S = “aabbaa” Here the number of partitions is 0. The string itself is a palindrome, so we don’t need to partition it. S = “abcd” Here the number of partitions is 3. All the characters of the string are different. Therefore the number of partitions is equal to string length -1. WebG. Palindrome Partition. Given a string s, find the number of ways to split s to substrings such that if there are k substrings (p1, p2, p3, ..., pk) in partition, then pi = pk - i + 1 for … edinburgh college mahara

Palindrome Partitioning - TutorialCup

WebAt each index, there are at most 2 choices: Extend the current substring. If the current substring is a palindrome, go for the next substring from the next index. As we reach the index strictly greater than the last position of the string, we need to store the path, which is a palindrome partition. Code for Palindrome Partitioning Leetcode Solution WebAug 28, 2024 · Hence the space complexity is O (n 2) O(n^2) O (n 2). Conclusion. Palindrome Partitioning is a way to split a string into contiguous segments such that each segment is a palindrome. Minimum cuts required to obtain palindrome partitioning can be found in O (n ∗ 2 n) O(n*2^n) O (n ∗ 2 n) time using the recursive approach. edinburgh college mail