WebFeb 17, 2024 · It has a calculator that finds all solutions to inverting the Euler totient $\phi$. I put in $16$ and it found that there are exactly six solutions: $$34, 60, 40, 48, 32, 17.$$ It also gives links describing the algorithm used to them (which involves traversing some tree) and the complexity of the problem. Share Cite answered Feb 17, 2024 at 11:44 WebSuppose that φ(n) = 2q. We divide the analysis into cases. Case 1: Maybe n = 2km, where k ≥ 3 and m is odd. Then by the multiplicativity oof φ, we have φ(n) = φ(2k)φ(m). This is …
Find all positive integers n such that $\phi(n)=6$. Be sure Quizlet
WebSo the only numbers n that are such that ϕ(n) is not divisible by 4 are of the form n = p ii ki is some natural number and pi ≡ to 3 mod 4. Oh, and of course we must not forget our case pi = 2. In this case it is clear than the only number n with a factor of 2, with ϕ(n) not divisible by 4 is n = 2 or 4 or 2pk11 where again pi ≡ 3 mod 4. Share WebFind all positive integers n such that \phi (n)=6 ϕ(n)= 6. Be sure to prove that you have found all solutions. Solution Verified Create an account to view solutions Recommended textbook solutions Elementary Number Theory and Its Application 6th Edition • ISBN: 9780321500311 (1 more) Kenneth H. Rosen 1,873 solutions Advanced Engineering … build creative writing ideas
Find all solutions of $\phi(n)=16$ and $\phi(n)=24
WebFind all positive integers n such that phi(2n)= phi(n) Prove that for a fixed integer n, the equation phi (x)=n has only finitely many This problem has been solved! You'll get a … WebFind all integers n such a. phi (n) = n/2 b. phi (n) = phi (2n) c. phi (n) = 12 This problem has been solved! You'll get a detailed solution from a subject matter expert that helps … WebThus, there does not exist a positive integer n such that φ(n) = 14. (c) Note that it is sufficient to show that if φ(n) = k has a unique solution then n is divisible by 4 and 9. … build creator - deepwoken tools