WebNov 28, 2024 · 1 Answer. You can actually first concat all strings and copy then into the passed char pointer. ... void concatinateString (vector stringVector, char* data) { string resString; // Concatenating all strings into a single string for (int i = 0; i < stringVector.size (); i++) { resString += stringVector [i]; } // copying the concatenated ... WebIn order to have the contents of the string be printed you need to get to the char* data that the std::string wraps. You can do this using .c_str() . Question not resolved ?
Convert String to Char Array and Char Array to String in C++
WebJun 9, 2024 · In the literal sense of your question title, you would convert an array to string like this: std::array buf; std::string value (buf.data (), bytes_transferred); Where bytes_transferred is the known size of the data in the buffer (so you don't have to rely on buf.size (), which would always be 1024). WebMar 29, 2024 · Method 3: Another way to do so would be to use an overloaded ‘=’ operator which is also available in the C++ std::string . Approach: Get the character array and its size. Declare a string. Use the overloaded ‘=’ operator to assign the characters in the character array to the string. Return the string. foliar feeding turfgrass
Convert array of unknown parameters from json into a final string
WebFeb 4, 2024 · You can't convert it, but it's straightforward to create an array: std::vector strings; for (int i = 0; i < list.size(); ++i) strings.push_back(list[i].c_str(); And now, strings.data() gives you an array of const char*. Note that strings should not be used after list has been destroyed, since it holds pointers … Web4. I allocate a char array then I need to return it as a string, but I don't want to copy this char array and then release its memory. char* value = new char [required]; f (name, required, value, NULL); // fill the array strResult->assign (value, required); delete [] value; I don't want to do like above. I need put the array right in the std ... WebAug 7, 2024 · This is closer to what you want without making a copy of the string into an array. just use a pointer to reference the chars. wstring timeNow = L"Hello"; const WCHAR* timeWchar = timeNow.c_str (); 99% of the time, the above works for whatever you need to do assuming you don't need to modify the chars. foliar feed